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0 D6 f0 f3 U5 P1 ]
3 i# ~. q: N+ w( h通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。2 _. G. g% C1 ]" {
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假设大路开这样的路:! f) O& _+ N R* ]) t0 }5 K
/ w" d4 O1 ?, Z 12121212121212121212121212121212。
7 ~* ?/ @: F, F [. R, Z k8 I- V2 ~) i3 L t8 h, G2 e' f
按2珠路,就是BPBPBPBPBP。& L$ m) @$ y; l* y |$ \- S
0 I) J- }. x/ h. g( Q s 如果我们去掉第一口,就会出现完全相反的结果:
& _ n8 [+ o0 s1 A+ T1 Q& l
+ q% N h2 S9 `4 W9 S 21212121212121212121212121212121。* z: B) j9 X8 B! w1 [. x
2 y( Z9 T% h9 j% n
变成了PBPBPBPBPB。
1 X( d8 J6 L/ F3 h, ~" S X9 ~) D$ H9 ~
- K [7 N4 ^3 y0 D1 g' y; L 如果我们再去掉一口,又返回第一种情况了。' m) N9 m4 S& p+ q% l
7 {& F% C2 X+ K0 q' B/ ~2 h' c6 K 所以每一条大路,按2珠路排列,有2种不同的路数。* @$ Y( R' J# \0 B! j. l
+ e+ k- n% V$ n6 J( A
再举一个列子:& S' m6 h! d+ Z0 a) Y! n9 j
0 v4 i' _3 F8 x 大路:122122122122122122。
5 l- o0 [* x0 D6 A! F
; j4 n1 Z$ ]8 Q c7 v 按三珠路排列:" Q* U3 }. t1 L5 A: `! B: f
4 C( w( \3 L: v/ `. L 122,122,122,122,122,122。
! |: [0 @+ @, j+ V' c$ V" m6 C( x$ f
) W- G* K8 k+ J$ c" Y1 w( G' N 去掉第一口,变成:
4 M/ h1 I9 w8 Y7 N/ `; p1 A6 n( C( ]- N; z2 A
221,221,221,221,221,去掉前2口,变成:
. q; d7 _; ~8 p D5 @, U: |5 f. {+ _- P3 w u( _! B
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。$ D! l6 v+ h. u7 Y
# K+ n F6 F7 _ B 同理:按N珠路排列,有N种不同的路数。) F5 l0 Z# e( t# N6 O6 a. G
0 O( f ?' m, X
我提出这个的意义在于:1 S+ c* J* g/ S5 {: T' }
0 {4 M* X) x) a5 l. L; z 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
$ K Y2 o: o( ]2 {; Q1 |
3 u: [% I* Y: c$ W4 | 2、为三多理论提供了下注的多面性奠定基础。# Z o/ o/ F) u: u' t# m7 f
1 b6 x% }6 _. a, }! ~* ]$ ]: v) i
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。3 e7 o( e/ v3 O, `: P$ E; ^; _
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