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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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假设大路开这样的路:
, G, z7 ~+ ]$ b' z s9 n0 j, U9 Z0 W6 |; ]$ q" r* P# H- m! ^5 ^
12121212121212121212121212121212。
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按2珠路,就是BPBPBPBPBP。% H/ {: _ k* }9 j2 P7 F3 g
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如果我们去掉第一口,就会出现完全相反的结果:7 i- l& O# f r
1 w/ p% `/ E+ w3 E, {: F 21212121212121212121212121212121。0 j# T$ ~; h- R7 c
1 o3 i5 n# P( R$ ^4 e$ ^" ~4 p3 w 变成了PBPBPBPBPB。
/ ]! a. l" ?: E. q c: y3 \7 K7 y6 M3 z
7 M: B3 h; I5 {4 k6 h8 J 如果我们再去掉一口,又返回第一种情况了。- h4 F# F2 ^( k- C/ \
8 a; \$ h0 m& H6 n 所以每一条大路,按2珠路排列,有2种不同的路数。 u Z8 z p& V7 l7 @% R* F, \0 i- A8 K
. C4 D# g5 M6 H: q 再举一个列子:9 @3 D& i' g" J
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大路:122122122122122122。
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9 u3 I2 o) b: V5 w" Z% }5 Q& w 按三珠路排列:
g# I p; ~- \ M4 v0 m+ l2 @! V
3 ]8 x& c5 H0 [- S# Z3 w 122,122,122,122,122,122。# T$ v; ^3 I9 _
8 `1 ~1 {: P; U0 U* S9 p 去掉第一口,变成:1 V8 n; l. p+ Q( ^6 f
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221,221,221,221,221,去掉前2口,变成:
`& d4 n; ^) {9 H' X% P4 _/ o. t- P
# o- d! P6 r" V) Z G7 m8 @* w6 Y% s 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。. l# N0 F( p2 N7 M3 q) ?$ A
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同理:按N珠路排列,有N种不同的路数。
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我提出这个的意义在于:& H/ U: Q4 V! V& C' Z' ] A) ^
, V, j0 h% s3 B% ?$ f% }2 m 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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; w/ L. D* c7 W" w# u 2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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