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[打法交流] 德州扑克手牌组合有多少种?(转载)
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1#
起手牌组合; T! i4 m  {0 d8 S. j* R

5 [) P- T' d) F* f# G( P德州扑克中可能的手牌组合数有C254=(54*53)/(2*1)=1326种特定的对子牌有C24=(4*3)/(2*1)=6种组合$ [5 j' A: q% b4 e) E6 @
特定的非对子牌有4*4=16种组合
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4 u/ L/ U% E; j3 J5 Z3 g: Y特定的同花非对子牌有4*1=4种组合
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! \1 p9 t  d, h7 m: s+ }# FAXs有13-1=12种组合% b! L; t; K) X. `. a7 |5 ?( I0 g

% F  X# M) R8 m. e% k5 m  z. AKXs有13-2=11种组合5 s+ ?$ k8 t& c) {7 N, G
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3 t4 r3 |9 {& u* e, I% {  D' H7 y7 h思考:去牌效应的应用。$ `% b# Y, O* _( n
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HERO手上有一张A,那么对手AA的组合还有多少呢?& I, y+ f4 i3 P( O% y

3 b) q$ R  F/ g答:有C23=(3*2)/(2*1)=3种,与你没有A时的情况相比少了一半。
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HERO手上有一张A,那么对手AK的组合还有多少呢?
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4 L: _7 L$ v+ N答:有3*4=12种,与你没有A时的情况相比少了1/4。
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手牌组合
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成牌组合9 h# F! o- |+ H; v3 v
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FLOP没有公对时:6 }' B+ j# Z1 D1 j

4 I/ L" ]" V7 z# F三条的组合有C23*C23=9种
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" o5 A1 R6 Y; l9 S( k1 j指定三条的组合有C23=3种
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两对的组合有C23*C23*C23=27种
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指定两对组合有C23*C23=9种
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TPTK的组合有3*4=12种& f" e5 ]" t/ u& q8 T% \2 j/ e  O
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- _0 B5 B: Y& M  u0 q2 p3 e7 Q" S+ PFlop有公对时:
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- o$ F. [- H# O6 h明三条顶踢脚的组合有2*4=8种9 ~0 D+ Z4 S( B, R

( `9 Y# a+ \. d. t* ?& r- \3 p0 D葫芦的组合有C23+C13*C12=9种  J5 u1 O& a' [# w3 S1 y

- w, r6 t% `5 C' ]' x' }' z& P7 F5 n5 G* I听牌组合; g8 i/ s8 ]! ?4 }: I0 X+ l* H" Q! x% l
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FLOP有两张同花时:( a2 q( k6 ^5 G& z; j; i- \
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对手理论上的同花组合有C211=55种, O4 s0 F, M: P' j* T

6 _; E5 o$ i7 {$ J' Q" I而当你手上有一张同花时,对手理论上的同花组合有C210=45种9 k& ~; u  ?: F2 {
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在类似K34这样的FLOP时:
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, P# @) f) H% T: A( ?, K两头顺组合(25、56)有2*4*4=32种
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卡顺组合有(A2、26、57)3*4*4=48种
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在类似K56这样的FLOP时:/ I  b0 g* N9 d8 K' E5 J" j+ x

0 u5 {: g9 u- U" u( f% ^" o) Q4 ?两头顺组合有(34、47、78)3*4*4=48种+ q! i/ D, h: w5 p, A

: T: X- e* S$ |, V) B3 ^- x卡顺组合有(24、37、48、79)4*4*4=64种# b- i- ^5 ]" w. O  w3 P4 G% N3 m

, w/ @7 E+ n% D& x: e思考:当你知道对手只玩同花连牌时,组合数会发生怎样的变化呢?(这个请大家自己做个计算吧~)
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参与人数 1贡献值 +3 收起 理由
avatar 天策-瑶娥 + 3 理论区转载发帖奖励

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2#
这个组合应该是很多的了啊。
avatar
这个组合也是要看一下的了
avatar
4#
知道有多少种,肯定是有好处的
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5#
主题回复处广告图案-天策传媒
你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了
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6#
感谢楼主的理论分享,也是可以了解到好多的。
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理论实践得好,收米的时机就来了。
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你估计也是一个理论很内行的玩家,感激楼主的分享。
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9#
老哥的理论打法也是有在记录中的呀?
avatar
10#
这个理论打法是需要向这个朋友多学习一下的。
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11#
基本理论也是要学学的了哦
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我的成果的功劳都是楼主像这样的理论分享。
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理论也许看着很牛逼,但是我还是不行
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这样的理论还是需要多多看看一下。
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这样的理论打法是十分科学好有道理哦,我也来收藏
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16#
老哥的理论打法还是很好啊,来收藏下了解下了
avatar
理论看看一下,肯定都是不会吃亏的。
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