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[打法交流] 德州扑克手牌组合有多少种?(转载)
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1#
起手牌组合  s. o# O' Q7 c) b
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德州扑克中可能的手牌组合数有C254=(54*53)/(2*1)=1326种特定的对子牌有C24=(4*3)/(2*1)=6种组合
. F9 m9 A: C" M( a3 z" S特定的非对子牌有4*4=16种组合* l  g5 j' s+ P6 [' i, I

1 T  H" ^! x# C+ l特定的同花非对子牌有4*1=4种组合
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/ d2 r/ t4 \( y' t) a+ B( t. BAXs有13-1=12种组合
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KXs有13-2=11种组合) o8 L5 y  t8 A6 ?
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3 E3 C& [4 a4 [& x5 V! |, i  s思考:去牌效应的应用。$ @' G2 I# c- V* q) L( F
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HERO手上有一张A,那么对手AA的组合还有多少呢?5 T* k, _6 C5 v1 G  P0 J3 J4 T

. f! `9 i" K3 n答:有C23=(3*2)/(2*1)=3种,与你没有A时的情况相比少了一半。4 T. }  d- q. X4 e' F8 S) L0 F

0 U; n8 q( C7 |. _0 lHERO手上有一张A,那么对手AK的组合还有多少呢?3 f+ _" _5 m/ @2 {. ^. A% I' F

0 K) a4 o2 m+ Q. K4 g5 a0 t$ n. `答:有3*4=12种,与你没有A时的情况相比少了1/4。
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手牌组合
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9 E# f% Y1 B  K成牌组合& Q# [6 [" V1 H' ~0 B

! O6 }" E) d2 Q% ]FLOP没有公对时:
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三条的组合有C23*C23=9种
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指定三条的组合有C23=3种
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0 j& T0 w% u, Z/ [& i0 X两对的组合有C23*C23*C23=27种! s( \% @: g! k: T6 B% o' D
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指定两对组合有C23*C23=9种& j7 H! c6 ^/ C9 @
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TPTK的组合有3*4=12种3 ?  _' ~8 ^  K" @# W1 K$ _- Z: Y
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Flop有公对时:4 B# L! N4 H" U0 N. ^$ w
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明三条顶踢脚的组合有2*4=8种5 I+ ~( S3 O" L
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葫芦的组合有C23+C13*C12=9种
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听牌组合
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FLOP有两张同花时:
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对手理论上的同花组合有C211=55种
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而当你手上有一张同花时,对手理论上的同花组合有C210=45种0 m- |, k  p1 t2 n
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$ S9 t( C" r& g# ~在类似K34这样的FLOP时:5 U( @! C4 n# x/ f+ ?
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两头顺组合(25、56)有2*4*4=32种3 P$ S! X' D: S% i; w4 e4 [

  U0 q0 r. }- A& M3 O卡顺组合有(A2、26、57)3*4*4=48种
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在类似K56这样的FLOP时:
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' T; z) s7 m) y9 l两头顺组合有(34、47、78)3*4*4=48种
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卡顺组合有(24、37、48、79)4*4*4=64种8 D) m5 u! m: V  o9 f

3 q9 q# i' y( Z0 F/ c4 L思考:当你知道对手只玩同花连牌时,组合数会发生怎样的变化呢?(这个请大家自己做个计算吧~)7 B/ i7 X5 `$ W& o" @

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参与人数 1贡献值 +3 收起 理由
avatar 天策-瑶娥 + 3 理论区转载发帖奖励

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2#
这个组合应该是很多的了啊。
avatar
这个组合也是要看一下的了
avatar
4#
知道有多少种,肯定是有好处的
avatar
5#
主题回复处广告图案-天策传媒
你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了
avatar
6#
感谢楼主的理论分享,也是可以了解到好多的。
avatar
理论实践得好,收米的时机就来了。
avatar
你估计也是一个理论很内行的玩家,感激楼主的分享。
avatar
9#
老哥的理论打法也是有在记录中的呀?
avatar
10#
这个理论打法是需要向这个朋友多学习一下的。
avatar
11#
基本理论也是要学学的了哦
avatar
我的成果的功劳都是楼主像这样的理论分享。
avatar
理论也许看着很牛逼,但是我还是不行
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这样的理论还是需要多多看看一下。
avatar
这样的理论打法是十分科学好有道理哦,我也来收藏
avatar
16#
老哥的理论打法还是很好啊,来收藏下了解下了
avatar
理论看看一下,肯定都是不会吃亏的。
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