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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。, [& Y# b8 R; m5 y8 d) E) b
1 L0 I- Y8 |+ ]* Y, n& T/ O 用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)! b! p) j; y0 T6 F) [+ B/ O
0 R) X$ k! ^* O4 |, g
第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)
- P& V* E1 k2 g( R. g9 _1 t0 A- S5 z- T
第二行:O X X O O OX O X (第二行开始出现洞)9 ]4 i% r# u( i) E& b
- e5 E: Y! Y* x$ W
第三行:O X O X X
4 A K; l8 ~1 G. k- \3 y& ^" j, b, z. I+ i# ^% p5 x
第四行:O X X
% d, y+ i$ D9 N d# p* n/ Z: o6 N+ S$ T! \1 z
第五行: X
! H; G3 V8 T. K9 ]6 M
) h6 V$ ` U" p+ L 那么新写出来的大路是怎么样的呢?
; [ k( x2 l! X6 _6 `7 D) @" n) E
" V2 I. k6 g2 F( P4 E% _ 记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。
/ S2 \, K3 s* J6 _6 |( r4 e' q* ]1 D3 D; p g. Q+ r G
如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)
6 C( h4 G: ]- W$ c! _6 X: f
+ R2 X. ^+ ~7 A+ `/ {4 ?# @. S, S 第一行:OXXOXOXO OXOOX(第一行不再是单跳了)
1 }% O* }- P: q; \
& N& n4 d: \) q( {6 @- g 第二行:OOXXXOOX XXXXX (第二行也是全满的)$ r3 |3 V) c3 _) ?" E
8 q4 P' Q8 N- Z# p# l7 D0 F 第三行:OX OX XO XOOX (第三行才出现洞)
; {9 u, j+ o r: B* L! ]6 [0 n) w2 M6 W+ Y1 q' Y; ~
第四行:O XO O XXX
/ t# b+ v9 W$ P# c) A4 e8 H
$ g# q5 D3 t4 R$ f 第五行: O
% Q: x% @: r! U4 `
# ~8 f C7 ?( ^ l) M0 ?! n8 y# T 通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。. v/ L+ V) ~1 Y# _0 ^. x0 V
& n3 E* t( { {" ~ 大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。. C9 U9 E4 o9 D. M
' @/ q$ j: { c0 Z3 ^ 通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。; W' {: X8 }7 y! J! J! k
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