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通过我几个月来对珠路理论的研究,8 U9 `* Z6 b6 ?' w/ F
. P6 j7 B5 D. P3 Y% q4 S. Y
发现了一个有趣的现象,
: ^& @: O, [- ^每一条大路,! e( w' s( P. w0 i5 o( S
按2珠路排列,有2种不同的路数6 h# F6 ?6 d) E' u5 C* u
按3主路排列,有3种不同的路数8 E9 _) J9 H6 h$ x6 ~7 Y
按4珠路排列,有4种不同的路数
3 W2 e. S) ?2 W按N珠路排列,有N种不同的路数。/ l0 Z- j4 ^+ v
什么意思呢,可能大家一时不清楚,9 i. {3 d1 \- I# n
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。2 p, k% w/ I% x2 E* J& P, A
假设大路开这样的路:
' h( z' B V# P% g12121212121212121212121212121212
* D7 p/ f. `8 d: j& ?8 b6 r够极端了吧
& [: c( m% [% T6 |! ~& I按2珠路,就是BPBPBPBPBP.....
# Q& M% ]( ~, p" N0 M3 w如果我们去掉第一口,就会出现完全相反的结果:1 Q# l; J# M0 y" `1 M' x. m9 K& F; H
21212121212121212121212121212121- ~; E. J k( [6 p o) T) ] X' t4 b
变成了PBPBPBPBPB......., J; f% t+ _! x! {+ \* ]/ k
如果我们再去掉一口,又返回第一种情况了。5 u/ c$ G- L5 K# T
所以每一条大路,7 z# _( u% t* r) A8 H B
按2珠路排列,有2种不同的路数。% I' g) n( [& w: x8 T) @
再举一个列子:8 ?* m: E5 A* H0 }5 D% u
大路:122122122122122122。。。& E8 t# j! ?0 `: ?
按三珠路排列:
. G" f4 _. E% C5 i122,122,122,122,122,122。。。+ d+ j9 |5 C3 @* K: s4 j
去掉第一口,变成:
; N5 x- k0 m3 g& K8 C* A221,221,221,221,221,+ ?( X6 K# O% X6 d+ m9 u" g1 q
去掉前2口,变成:
( H3 Q) @- r1 x/ u' K212,212,212,212,212, n( \5 R; T1 |+ c) i6 Z* V) c) f. j
去掉3口,又返回122,122,122,了% @4 m) T& P9 O* c+ u
所以每一条大路,% U) ?* V/ w" q! F( {
按3珠路排列,有3种不同的路数。5 W: [2 @1 q2 A8 S# l; G
同理:按N珠路排列,有N种不同的路数。6 J% ? m7 W1 h0 ?+ d: j9 j; n
我提出这个的意义在于:
/ ^% x9 \5 w5 f& Q! L: G8 Q6 M) }字串8
$ E' U2 ^7 ~9 F% R! j$ i7 @/ k
0 m7 o7 B$ O& ~: Q1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。8 w" e1 _! o* L4 t
2、为三多理论提供了下注的多面性奠定基础。" e9 k+ X& [1 Y- _; v/ F9 o
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.
/ }* K" ]1 P! U# g. N* j3 O5 I4 v |
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你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了 |
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习 |
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。 |
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