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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。" r$ H& i0 _/ q' ^% t
; s8 ~3 l; {6 Z8 |0 ]+ y1 P
假设大路开这样的路:. C) A) J h6 T9 b+ B" `4 G
5 k- |' \; u/ |8 L! z0 A9 o) V ]1 P 12121212121212121212121212121212。
' B! r; f0 U/ j% M( W; L9 D* S& F( Y* {' r" T
按2珠路,就是BPBPBPBPBP。9 p! y; F% ]! |
: y" [1 F* b8 g) ]% Z
如果我们去掉第一口,就会出现完全相反的结果: c) R) ?: [- b: T8 j9 I
5 I5 K, y3 F6 Z7 ~6 E6 t& t 21212121212121212121212121212121。
5 O4 ^ @9 e0 V
3 m7 x3 a& u4 c1 W 变成了PBPBPBPBPB。6 p ?# Q4 ?+ f7 w9 a% ]& X7 T4 C
; I( \6 g0 S O8 x4 | L, `' T
如果我们再去掉一口,又返回第一种情况了。 V3 H1 c# E1 M% e3 s# Z
) N( }! k9 k) u6 n+ b1 M
所以每一条大路,按2珠路排列,有2种不同的路数。
! H. b } n+ q3 H8 b8 m/ Q3 D0 T' V! M5 l- S2 X+ T
再举一个列子:
; p/ ~- \6 Q: u/ V7 D1 h( W/ N& U
大路:122122122122122122。
) C% @" S6 N$ z( `6 g q. f/ n8 Q, }; l f
按三珠路排列:8 E8 m6 k4 _( E) Q
7 a8 z6 K0 {6 w2 b% y \ 122,122,122,122,122,122。
# V v& Y0 ?- ], d# t5 P% l$ W0 v @1 m2 l5 y* \- y, J
去掉第一口,变成:: N+ {3 Y& Q, c7 X J/ ^
2 D2 r. K: ?* J6 s) W 221,221,221,221,221,去掉前2口,变成:) H1 {# D, k7 Z. T; v2 p
( r6 P( t) A. _5 k3 } 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。9 t5 J8 ^9 u2 h& a) ?& F! V
9 o) O5 ]' D4 `+ {+ K4 y; X
同理:按N珠路排列,有N种不同的路数。1 R6 T8 K4 H& X- s; g7 v! D7 H
1 N$ u$ e4 O$ t
我提出这个的意义在于:
+ M9 n6 l8 h$ @9 h& S. H/ F' Q4 Y' c
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
8 N! N/ ^7 Z1 h" l1 h; H8 J
1 d/ {4 O+ ~/ f( D 2、为三多理论提供了下注的多面性奠定基础。! l- d; y0 R" H% l' a$ q
$ ^4 C x2 ^9 b
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。" W" c6 y# Q: F: M- n% o1 e, W7 t
, M: `# n: y5 W |
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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