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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。7 w) I% f( ]3 w& l2 k3 N! D
. `7 D$ N+ v) N1 i9 `一般来说,2 U! e; W4 p) L
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二连赢的概率是25%& K! H6 b" H9 o* A% `4 S9 N5 B! j
- q* \& ?$ Q/ L# Y1 p2 C) |三连赢的概率是12.5%5 x3 v) W" H8 b
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四连赢的概率是6.25% K$ l {% `4 @" o8 U* G
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……3 H0 h$ Q6 d8 y. f2 U
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十连赢的概率是0.09765625%
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这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。9 t/ Z* K% o: i4 A$ x& H1 S" p
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百家乐的真实概率含义是:
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# l% f" |0 X; r) \# M* A' \假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球
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) c- w! C* `) t6 ^* S0 R1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。
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& f7 M% c9 t' F- ], z你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。: I5 l, x8 J+ ]7 w) q# n
- H$ q9 j: `8 `5 o" H你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
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另外一个说法是,
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1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。5 `# o x* L9 s [' b
) ^; M4 W8 `+ t* c7 L; Y W+ r2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。" f# p, D9 u% v7 Z' B% P. m
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。# Z# Y" a5 q3 T9 q
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平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。9 ^0 K$ T$ O* U* J
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
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' g' V; M& B" d9 S0 {0 O7 @举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。
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第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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第三,凯利公式的问题在于:形而上学。. x6 w$ t9 m" Y k& _8 y
9 U5 o9 }) b4 j0 v2 @+ K/ ^首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。: {7 g0 z8 N' t& r5 w
4 R! A2 Z5 O7 Y* R5 F s7 b事实上,你玩的时候,基本上每次都能打到。. r* M% e6 K; \0 V
7 [! m8 ]* p! l) k( P, \9 C
因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。( C! n% F6 k' Y0 H5 n# u: Y
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