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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。
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" d% B2 Z R. L; H一般来说,
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. ~. b6 e* u# `, e二连赢的概率是25%1 j; I1 n) s! F: l0 v! \& T' n
0 P$ S- Z8 {1 o& I9 s三连赢的概率是12.5%! C" ]- g# D. U* F; L# W+ h
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四连赢的概率是6.25%: R; a. Z( ^6 Z
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……
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% p3 R4 @; A+ l0 \ ^# ^ }十连赢的概率是0.09765625%, ]5 u, q( m" \2 a* [1 @% C
* G( ~( c0 o, Z0 v) h9 t这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。
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百家乐的真实概率含义是:
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假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球
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1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。
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& B) b+ g1 s8 T0 y" N/ B0 G你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
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另外一个说法是,
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1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。* V2 M# X, Z4 N" G `
. Z4 a" n; K& b$ }- n2 [8 H2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。' {: Q2 C2 }; ~0 M- }5 V" U
& X6 w" I7 M0 a2 I再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。) [4 ~- p* Y4 q" v7 U( o5 _7 p
* D) |1 {" G& i0 Q6 h5 C& h平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。; \9 s; x1 b5 q# [! N3 p9 p; ^
, g5 n; p# f) {; C6 K& D( p6 ^举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。: O3 N2 \, S+ s# ~7 l6 Y
$ ~ O0 g4 N8 _0 e第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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" B2 Z$ q! O3 T- ^9 j4 O9 b& z$ @第三,凯利公式的问题在于:形而上学。. S% @$ f% h- X% }/ C& F0 F
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。1 |* F( B5 U/ d4 q7 d
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事实上,你玩的时候,基本上每次都能打到。
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/ q5 T5 m0 [- r& A, M因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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