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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。
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5 {' n9 x# ?" W5 v- b一般来说,
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二连赢的概率是25%
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三连赢的概率是12.5%
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四连赢的概率是6.25%
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" C1 P/ G9 p! I# M* Z……( ^( i9 F- [" r: f5 N) b
: ]7 l' d, H7 }3 \, ^十连赢的概率是0.09765625%7 X2 |+ y. V4 J T+ v
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这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。/ s+ r, ]0 D9 `3 Q2 u4 d
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百家乐的真实概率含义是:* G% m5 i; H/ B: V0 {% C4 L$ \2 q
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假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球
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8 Q, M* P/ t4 e4 g8 W C' r1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。! i. C" L& @1 G: Z; i- G" z
" U. p# R1 @ T' s你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。5 }$ A2 \+ }+ P' a9 b! G" @# T
# \0 p E4 v5 X* P, o你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。% Y, K I/ @7 @" X
! p3 X' C! J( S' s6 Q- U另外一个说法是,
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1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。9 V4 x9 @# L) h+ H# G
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。. x6 b0 B+ t" S9 \
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。! s: T% ~& w7 `9 M5 m
8 ~4 {! U8 o4 O) p+ B平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。& E3 V2 W' F2 o5 _$ ]
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
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举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。) U/ r5 m1 J4 b @" E" [0 n3 g
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第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化+ E7 U9 V" g+ n# ]% d
& n4 P4 \9 i8 ]$ j) n) ]: Y2 y5 u2 n; B第三,凯利公式的问题在于:形而上学。
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。2 W" ] b: G8 z" P
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事实上,你玩的时候,基本上每次都能打到。( {# q/ T: \" z4 q0 O
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因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。5 d: j( c L3 x2 B4 D. R/ e+ K4 u
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