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2 |! ^5 U1 l: J9 W7 e, _+ _
) w+ F7 p* V+ U" |. M5 N1 ^9 o+ ?
通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。" z( {9 o5 S* c% ^1 K' \
c4 w7 F; @2 |; L: r' R/ y
假设大路开这样的路:
3 w+ k- w4 z L0 v0 I% S% h
$ m* M% i) ^3 @$ M" g+ V& x( A 12121212121212121212121212121212。& f5 f+ _% u$ B2 @
% |2 X. \- e; _' E
按2珠路,就是BPBPBPBPBP。
% \* m% E+ B% z M2 V" q
! z# ]7 A7 p9 d: ~* A' m 如果我们去掉第一口,就会出现完全相反的结果:
' a1 v0 y/ ~2 z) U9 S9 `% y# M+ y% w# \9 m( v/ q5 W! l6 x) ~
21212121212121212121212121212121。 G, z0 C# G6 y/ H7 f
! X( l) `( C+ A; B6 c 变成了PBPBPBPBPB。0 X) H& _5 {( O) M6 X
& D0 F. ^, y9 C: m8 ~ 如果我们再去掉一口,又返回第一种情况了。! x; z, f# u* K8 m6 X
! k* h0 ?% `( q0 }& W 所以每一条大路,按2珠路排列,有2种不同的路数。; K( H! _& \" g4 ]$ \1 n
+ ?# F4 V( M* P& c, u) v6 I
再举一个列子:$ [5 E5 q) j3 E% }& ]6 I! R
! \, U5 ?7 s' i
大路:122122122122122122。% v( \/ ]. l$ |$ L. J) C6 \! Z2 ]
$ S7 V% p3 U3 M
按三珠路排列:
0 ?, r+ e8 W" J) f7 @& i% @+ u' y i
% Q7 }( I. }8 @$ b" A \6 d9 w 122,122,122,122,122,122。
9 `5 ~& u7 e$ [6 R4 n$ D( z. D4 ~. Y0 ~; ~7 i! r6 i
去掉第一口,变成:
2 j7 c+ @% @3 \) @" x! N' Q' M8 \3 w& C8 e0 n
221,221,221,221,221,去掉前2口,变成:
_( Q3 d |: ?/ H q" Y+ Y2 e+ f
6 J1 Q( J" f. u' a: B/ j* X& k 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
A) g! }- ]" p6 T6 D' E; ^
! q2 k4 ~, S2 q8 Y, p( v5 o/ o 同理:按N珠路排列,有N种不同的路数。+ G V7 j8 Z/ z! P. x: t
" {& n9 a( X F/ q9 x. ` 我提出这个的意义在于:6 j8 v; d& a* R2 D
9 w f7 @/ F- M* k8 S 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
# P/ @& {2 K5 V/ X' @2 b) O5 W0 a& | H4 E% z9 f
2、为三多理论提供了下注的多面性奠定基础。9 P4 a& M) } r3 c
. B; q) a/ z* j# a* U
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。& ~6 ]2 v0 T# Z% @
1 M) Q8 w8 A7 b+ ?6 d+ _7 v- B0 u9 z5 I
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