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- b( P3 a% t/ ^; f2 Q! `
7 y) i/ z8 t9 H9 C通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。# G7 U {9 c2 ]2 |; d7 y' @) J. z
; b8 i( [" j+ @. V 假设大路开这样的路:- a9 R! @4 d0 t( D, A: m+ n
1 P. A9 T& V# o! q7 S9 N5 ]
12121212121212121212121212121212。9 ?9 Z& u6 t6 I8 U u2 o* r
; e# c3 v% Q+ B3 ~% M5 n
按2珠路,就是BPBPBPBPBP。: y4 w9 Z# U' J' k6 q1 E1 K5 ~, R0 U
& n0 \7 X* H& a; ~. T7 [& e4 K' y 如果我们去掉第一口,就会出现完全相反的结果:
9 P- b3 U% W% [: `
! i6 ]' L5 b* a/ ~7 _1 } 21212121212121212121212121212121。. c P- }/ J( M" O( K5 A. W) _
8 q4 z+ G) a+ G) {
变成了PBPBPBPBPB。 Z# }& W; [9 t7 S: k& V
, B+ h5 B: E7 m3 z7 t9 w f 如果我们再去掉一口,又返回第一种情况了。$ N, D; O; }( T
8 b% m+ c, p" G
所以每一条大路,按2珠路排列,有2种不同的路数。
. l! S: X/ l: P. T9 X) C1 B/ ]
' v& G4 `9 m z0 ?! D 再举一个列子:
8 r( s- g5 q9 O6 ^/ \6 n B
$ b# r( g$ Q/ E5 ^ 大路:122122122122122122。 v/ L9 t( k5 r
) n) ^( O3 a/ M+ M4 \0 t0 O7 }
按三珠路排列:5 ]0 r- ?% e9 t/ P
2 f, g) B, B. f* M7 T9 t' g7 r
122,122,122,122,122,122。
. T. O9 q5 z) |$ X8 l+ T' H& d% C8 E& D7 k2 l( T( E
去掉第一口,变成:
" V7 s5 b+ x5 i$ C( ?- N/ `1 H- j9 w" r+ ^* y, o( s" |3 m
221,221,221,221,221,去掉前2口,变成:
+ \0 ?& r9 F6 s- G; o/ `- t/ ]: p3 O% Z; }$ U' e; W
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。& H- c& l7 R* g5 d# `1 K0 v7 M
' G: [8 p( l; K& W& a 同理:按N珠路排列,有N种不同的路数。
8 H" Y, A# x5 Y( ]1 _+ G) l' p& i1 K/ v& u \9 t
我提出这个的意义在于:
9 l5 U4 L9 i6 z2 k2 v* I' e: U, U. y6 k0 `& [
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。6 D1 j! P# t7 J: a
l" O' G2 u7 F6 k+ @3 z$ m
2、为三多理论提供了下注的多面性奠定基础。$ V$ I7 C; N) H7 Z' R& A' Y4 e
) h, I2 G0 {) A+ y 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。* W4 A; ^) H S: T
: `; g0 K" B' K" Y8 T7 ~1 N7 F
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