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[lastpost] => 2777111 【吉祥坊】10月28日投注流水1000元 1761657636 22301
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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假设大路开这样的路:" V8 A* z4 B( m1 F6 R8 v9 V1 q
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12121212121212121212121212121212。4 ^/ C# a9 Z; d7 ?; a, E! ^. j
. i1 f3 P$ t X 按2珠路,就是BPBPBPBPBP。
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( q# q% s9 b- |# k1 s6 | 如果我们去掉第一口,就会出现完全相反的结果:
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21212121212121212121212121212121。
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变成了PBPBPBPBPB。& d/ [) p+ i i- o& m
) P, ~* \5 Z7 [7 |5 a! A 如果我们再去掉一口,又返回第一种情况了。1 e0 S. V4 w3 h: r. R& l8 K
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所以每一条大路,按2珠路排列,有2种不同的路数。
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再举一个列子:- _: ~0 e2 L# d. P
% L( u7 f% G& p& J 大路:122122122122122122。
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按三珠路排列:
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122,122,122,122,122,122。( `7 D1 \/ Z8 S
3 w* H5 f+ `+ E, d 去掉第一口,变成:+ X6 j+ S( B1 p' w0 \# v
7 C$ j# d' S! x" q/ c/ K6 } 221,221,221,221,221,去掉前2口,变成:
0 o$ R7 Q+ R9 y/ f2 @& C! ?6 G0 o1 y% d" F9 {% x2 w6 l
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。0 V O3 Q b; a8 J: s
0 K* y6 m& w/ }; z* O; G 同理:按N珠路排列,有N种不同的路数。
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6 x! y8 v+ X$ W2 k; m 我提出这个的意义在于:) s5 ^, i# g0 s z5 C
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。* [3 D4 m% X; {0 q% n! @' n
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2、为三多理论提供了下注的多面性奠定基础。. B1 R6 J" s* z
& {" j2 U+ V" K0 G8 t2 u 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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