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相信大家对断组不陌生吧!断组形态3-3-4,也就是说每期开奖号会开在一组或两组中,断去其中的一组或两组,通常大多数情况下是断去一组!' c$ N$ E* I- e6 T8 t
首先此方法是在号码对应码的基础上创立的!$ l/ _* N& r; A3 l9 I# e
差5对应码:05 16 27 38 49
8 C) ^( ]2 A4 |% R# s( W& G和9对应码:09 18 27 36 45
/ O" h5 W$ z l5 v' `4 b: L断组方法中出现的几种形态及解决方法:
: d: H2 [" Z4 F. E形态一:奖号中3个号码无对应码关系
6 a& ~, K" |1 A( |* w例如2009250期开奖结果为319,号码中3个数字无对应码关系,这种形态断组比较简单。
$ p6 ~; s1 h) h% _; Y断组步骤:
0 Y9 p& Q* X4 i6 p第一组用319的对应号码组成!3对应8,1对应6,9对应4,得到第一组号码为864。: ^8 T# b- k. V0 W9 ?5 C/ x
第二组号码用第一组号码进行和10,8+2=10,6+4=10,4+6=10,得到第二组号码246,但是这里问题出现了46两号已经在第一组中出现过,那么这里我们就使用46的对应码9和1,最终得到第二组号码291。- Z7 W- G8 H3 v3 Z( U o
第三组号码简单了,除去第一、第二组的号码剩下的四个号码为第四组,得到号码0357。8 S5 Y }! |6 G- }1 O, v
综合起来:864-291-03576 C+ ^0 E$ P# }3 @% i; N
2009251期开奖结果为587,断去第二组号码291正确!!: S/ _& v2 k; B# U* C7 u' A
形态二:奖号中3个号码中有2个号码出现对应码关系(这里对应码关系我们只考虑差5对应关系,和9不考虑); I9 D/ I. M4 O& L0 k
例如2009242期开奖结果为156,号码中16出现差5对应关系!. n! ^* y% |/ n6 x* l' U- B
断组步骤:
9 U4 F! }0 e2 P第一组保留奖号中的对应码16加上5的对应码0组成第一组号码,得第一组号码为106。. {0 B( D5 g E7 X
第二组用第一组号码进行和10,1+9=10,遇0使用0的对应码,6+4=10,得到第二组号码954。/ p2 m! q3 K, C- d( y. U, G1 R
第三组为剩下号码!) |: ^, i4 D) L
综合起来:106-954-2378
S9 N0 `& P$ S% M' H( W2009243期开奖结果为695,断去第三组号码2378正确!!. A, H; v7 D% z; T8 i
形态三:奖号中出现对子的情况(也就是组三形态)
7 i: ]! z' z B- c, S5 z例如2009253期开奖结果为707,组三形态。' `2 g) s6 J7 U) a& F9 V. w
断组步骤:4 i* M. ^ w/ c/ Q& J8 `/ |
第一组保留对子中出现的号码7,加上0的对应码5,得到第一组号码为057。
( f9 f e, Z( D第二组用第一组进行和10,遇0时用0的对应码,这里问题出现了0的对应码5在第一组中已经出现过,这里我们使用0的和9对应码也就是9,5+5=10,而5在第一组中也出现了,那么用5的对应码0,而0在第一组中也出现了那就只能用5的和9对应码4了,7+3=10,得到第二组号码为943。' F. C* J8 \1 g1 h
第三组为剩下号码!
1 [$ j! g7 X: W1 `" ^8 F综合起来:057-943-12684 Z" B9 I: U: B4 k( ]
2009254期开奖结果为008,断去第二组号码943正确!( j) H& U) `2 T0 e$ Y& l" x
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