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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
; z% J' A K6 [, n B7 J! _4 d1 _. j. Q6 {
发现了一个有趣的现象，+ O, r/ S& d+ H1 E/ u
每一条大路，
U6 T' g/ Q5 G! D1 p) i按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
% z0 Q4 r! _" b' m$ F, t2 m按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
# |4 X' T, m& ^6 E按4珠路排列，有4种不同的路数
1 z- a; C, ?- V8 f6 ~) S# D按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C2 {4 v4 @! E5 _3 t7 K9 t' M
什么意思呢，可能大家一时不清楚，
' p( L" `- I% |' b0 g我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l3 |6 `; c3 C4 b+ y: o/ a& m W
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
' v0 u& n& f) N12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h; a5 ~/ w, K+ B. L/ k3 [# R A3 V
够极端了吧' L9 ^- u5 |- n+ \9 O: \. M
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
/ k" O# |& q; R如果我们去掉第一口，就会出现完全相反的结果：
0 o" N, W X% x# c% ~) p4 e. z& z21212121212121212121212121212121/ Q* p0 H, r1 X2 w
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
9 I; x4 s% A7 x6 Q/ f1 f3 ^如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
: X! H2 m3 e+ s; W5 @' {所以每一条大路，! R6 V# q$ h. c; z% O3 V: J- _+ T' C- R
按2珠路排列，有2种不同的路数。 I# ~; u9 T" f7 Y0 y) v7 @
再举一个列子：
! a2 [2 g9 k1 [" r0 G6 k( N大路：122122122122122122。。。
; r4 A* j" O6 @# m, }2 W4 b1 A1 N按三珠路排列：
8 T, ]$ L; X7 I122，122，122，122，122，122。。。
9 ~; B# a% x; z) H7 s去掉第一口，变成：6 G2 V! \" L' c" k: d" n6 w9 i; ~% \1 ?
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
0 I0 Y Z; U0 q$ T3 E# P去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W/ F7 x5 f2 @9 p8 b1 c
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `$ o, ]* b/ r) }) [" l& p
去掉3口，又返回122，122，122，了
1 m/ u* h7 \( [$ p/ D所以每一条大路，" ]! x4 X) D0 |& @/ E
按3珠路排列，有3种不同的路数。
+ o9 ^6 O3 ?- ]9 e) [( Z5 g) i1 Z同理：按N珠路排列，有N种不同的路数。
. Y! s. J1 |: U. Q1 O y6 \8 e7 W我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O, h: z' O+ A% q- O; c
字串83 L: R) G1 V- s2 Y+ Y+ ^+ K, j0 E* u
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
! ]6 L0 S o# y7 f+ g! I1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |# k8 u# x: X9 S a1 f+ S/ ~
2、为三多理论提供了下注的多面性奠定基础。
$ f- t6 g% P. A$ g1 }3 v) r6 N3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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