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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O' s1 o2 o% G6 q5 `7 z
; h Y. ?" {# \- Y2 C- Z3 t: \
发现了一个有趣的现象，
6 W$ M7 c/ f7 b5 N每一条大路，2 C( a d1 t, y- K* K$ R
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f! V! I3 b9 Z( u2 {- g! H
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z- f6 T0 ^2 }+ ^4 N% a. N7 M' {
按4珠路排列，有4种不同的路数* J; o9 P; w; Q# u/ n
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C" |5 A9 l4 O5 {& o% U" p" D2 Y
什么意思呢，可能大家一时不清楚，
B! Z7 O [/ P0 ]" p0 F& \; j我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
" ?7 p; n% M2 l3 I" a2 E) {9 Q假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
1 ?! m5 u7 M, I O6 J# e9 H12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h% J% j- O3 z& B
够极端了吧, O- C3 W$ E& ?4 M6 M
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
' @( b. p; ~0 K- t/ |4 ?如果我们去掉第一口，就会出现完全相反的结果：
; w6 x% G, F$ ^" v" v3 ~2 i7 Y+ n212121212121212121212121212121216 D2 Z! t* z( ?" v9 `
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C( @, M9 m, Z9 `/ a- k2 c0 p* z
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O4 [1 Y- S% x& ~) m1 ]5 h$ [
所以每一条大路，! R6 V# q$ h. c; z% O
4 z3 t( { D0 r4 V* y按2珠路排列，有2种不同的路数。/ o; l, g; _8 V* T# B: j
再举一个列子：
# H) P8 e& d% B" ~! G" p0 F大路：122122122122122122。。。& a5 N( p( Z' j( g3 J" J
按三珠路排列：
. v+ z* O* W9 c6 u x* r* X122，122，122，122，122，122。。。
# V4 u3 {7 }* P& z R5 Z去掉第一口，变成：6 G2 V! \" L' c" k: d2 z" J9 z5 u# }4 L, \
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
( Y, p% S& i C去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W! E1 L8 d( @) B* K% y
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `- A. r/ |! r; @
去掉3口，又返回122，122，122，了
+ Q% t- @0 L$ t* u3 X所以每一条大路， P) O" _% S' }; z5 v
按3珠路排列，有3种不同的路数。9 z* H, x/ |/ }: s1 o" Z: N
同理：按N珠路排列，有N种不同的路数。0 ^+ ^ _; x1 p
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O0 D' N) z* b& C9 {1 t+ |8 S
字串83 L: R) G1 V- s2 Y+ Y0 [) S9 C) P F
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @: c+ w6 p: [. v8 _ P6 L+ A% Q
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |# k+ F- L' _8 R' z# q" }) o
2、为三多理论提供了下注的多面性奠定基础。- I, g, A! Y! A! q: t+ `
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.3 ?- [" N) [% W
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