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[打法交流]
体育博彩中串关赔率计算方式和输半赢半的具体例子(转载)
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在下注体育博彩的时候,足球和篮球的串关赔率一般是怎么计算的?输半和赢半的时候要怎么算呢?
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串关赔率计算方式为: 金额 x (1+第一场赔率) X (1+第二场赔率) X (1+第三场赔率) X ................... ===================================== 三场全赢 100元 X (1+0.95) X (1+0.84) X (1+1.10) = 753.48 元 (三场全赢) ===================================== 一场赢半 金额 x (1+第一场赔率/2) X (1+第二场赔率) X (1+第三场赔率) X ................... 100元 X (1+0.95/2) X (1+0.84) X (1+1.10) = 569.94 元 (2场全赢,第一场赢半) 此处赔率只有一半 ===================================== 一场输半 金额 / 2 X (1+第二场赔率) X (1+第三场赔率) X ................... 100元 /2 X (1+0.84) X (1+1.10) = 193.2 元 (2场全赢,第一场输半) 输一半,直接除2 应该很清楚了!!! ===================================== 串关赔率奖金= 赔率 X 赔率 X 本金 - 本金 - 以3串一为例,三场比赛的赔率分别为0.9/0.95/0.94,如果这个串关下注了20块钱,那么这个串关的奖金就为:
- (0.9+1)*(0.95+1)*(0.94+1)*20-20=123.754元
- 如果三场比赛中第一场比赛只赢一半,那么这个串关的奖金就为:{(0.9+1)*0.5}*(0.95+1)*(0.94+1)*20-20=51.877元;
- 如果三场比赛中第一场比赛只输一半,那么这场水位就不计算了,把剩下的2个赔率拿出来计算:{(0.95+1)*(0.94+1)*20-20}*0.5=28.9元
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