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解析1.76亿中奖概率:428万分之1而非4.4亿分之1
 
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1.76亿!6月27日晚,体彩诞生首个亿元巨奖。一夜之间,重庆彩民中得1.76亿元巨奖的消息引起了大家的热烈讨论,不少人甚至开始计算1.76亿元巨奖的中奖概率,有说是2142万分之一的,有说是4.4亿分之一的,也有说是428万分之一的,今天我们就来谈一下中奖概率的问题。 
8 n7 l# d6 v/ g4 ~9 G+ r  |[b]如何计算一等奖中奖概率?[/b]$ G) f0 m- ]+ u: P 
每期摇出的奖号是一组数字,每个数字的出现是有一定的概率的,那么一等奖的中奖概率该如何计算呢?1 y3 u7 u# @$ ?" ~$ C! o 
以超级大乐透为例,购买者从01—35共35个号码中选取5个号码为 前区号码,并从01-12共12个号码中选取2个号码为后区号码组合为一注彩票进行的基本投注,则一等奖中奖概率为:0 B7 b4 s/ }& X; K6 q' z4 o 
前区号码组合总数C(35,5)=324632 
. e* E/ U7 b# }" x1 O9 t/ w后区号码组合总数C(12,2)=665 Z2 e. Y0 s. r+ e" K; s5 d7 p 
一等奖中奖概率=1/(324632×66)=1/214257124 U& g# e6 x, F* Q- f 
简单来说,假设某彩民采用包号的方法,对所有前、后区号码组合进行投注,即投注了21425712种不同的号码组合,那肯定有且只有1种组合与当期开奖号码完全相同,也就是说他100%可以中得一等奖;如果彩民仅投注一种号码组合,则一等奖中奖概率为1/21425712。如果投注两种不同的号码组合,那么一等奖的中奖概率自然就增加一倍,以此类推。+ O, [' d$ B  v9 g  K 
[b]4.4亿分之一的说法是否正确?[/b], a$ J; B/ ?# H  z) a5 i 
重庆02818投注站中得的1.76亿元分别来自两张彩票:一张5注单式票并进行了追加和20倍倍投、一张7+2复式追加票,因为尚不能确定这两张票肯定为一人中得,我们这里仅分析20倍投的单式票。从票面信息来看,单式票上的其中1注号码与当期奖号完全相同,因为进行了20倍倍投,所以是中得了20注一等奖,另外1注则来自该复式票。需要说明的是,中奖概率只与前、后区号码组合的数目有关,20倍倍投只是提高了中奖后的奖金,但与所选号码的中奖概率没有任何的关系。即使是倍投99倍,但中得一等奖的难度并不会随之提高为原先的99倍,所以4.4亿分之一,即1/(21425712×21)的说法是不对的。% I7 H- ?0 S$ ^3 g( [5 [ 
[b]428万分之一如何得来?[/b]1 J& I9 x, V, w2 J 
在这张单式票中,该彩民共选了5注不同的号码,因此5注号码的总中奖概率=5×1/21425712,即该张彩票的中奖概率为428万分之一。  t. ^5 x8 ^6 s5 D( J 
[b]中奖概率低仍受热捧 原因何在?[/b] 
' O6 ^& Q/ h5 m# P* e. V2 D+ C8 v1 T仅从中奖概率来看,中得一等奖的机会是很小的,但是超级大乐透仍然受到了很多彩民的热捧,因为这种全国联网大盘玩法有巨额奖池的保障,一等奖奖金十分可观,这从全国动辄中出的千万元以上大奖可见一斑。: Y: L1 M# H; z: S5 w4 r! f) c 
[b]常见误区:超级大乐透不易中[/b] 
3 ^5 y  Z  |( H: P* q) x$ w4 @不少彩民反映超级大乐透不易中,其实这是一个认识上的误区,同样我们从中奖概率的角度来进行分析,仅以八等奖为例。 |   
 
 
 
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