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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O& a; Z7 p) F0 O0 [6 G
7 V% [! o4 ^8 Z发现了一个有趣的现象，. x/ H+ ?( B' Z! p$ O" T
每一条大路，
9 W' c3 @# a$ h7 D按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f9 |' Q* _- V+ O3 Y9 Y4 I
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
7 h ?$ `( B) x" G' `6 D" ^按4珠路排列，有4种不同的路数8 d+ p* `+ t! Z9 N& h0 L: g! z
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
/ L6 T9 g3 v7 d9 Q1 l9 G# T什么意思呢，可能大家一时不清楚，& q& \: i% u2 ?/ A
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
! M( A; P. c7 W. X. G假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
4 B0 X* o7 Q/ V12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
7 d+ s9 g" X+ ^: C够极端了吧# P7 Z9 A. M: m9 Q" ?+ h
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F1 Y X' x2 V. v0 F/ j- b
如果我们去掉第一口，就会出现完全相反的结果：5 k/ s1 W; d' ^. |! [5 }
21212121212121212121212121212121
5 d+ K2 G" l' ^5 M p: Q* v$ G变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C1 k( f9 X) {. i( s. ^5 e$ l
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
9 N; s0 k0 O2 y' Y/ Y5 n. m& A所以每一条大路，! R6 V# q$ h. c; z% O
: }. _8 j; h8 K g9 W按2珠路排列，有2种不同的路数。
# f y9 O5 {+ v$ L& Q) K再举一个列子：
- I/ Z; \2 J+ o大路：122122122122122122。。。
+ S) g2 J7 Y; ^* ^/ \! b; {按三珠路排列：9 l0 Z6 ?% o+ f# ]8 B
122，122，122，122，122，122。。。& m+ \9 i2 V9 o* T" V
去掉第一口，变成：6 G2 V! \" L' c" k: d
: G# S9 f2 N& ~3 J221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M% g# W( J4 {; T/ _5 @! C4 ~
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
' J( h* D5 s! A# d3 f9 S212，212，212，212，212，: y& l, B; I6 e- m. J# c) `( k W$ \7 A2 U2 _8 ^( t) X0 ~. m
去掉3口，又返回122，122，122，了/ K: J) r) m: i4 n- f: I6 O, T
所以每一条大路，( k b* F2 Z* f- t+ U
按3珠路排列，有3种不同的路数。# J- U; ]7 `8 I7 e ~3 x6 B" B
同理：按N珠路排列，有N种不同的路数。3 u: M) B, s2 W( B) T2 N6 x
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
2 `& i0 B# v" V: j$ ~, u, `8 o3 s字串83 L: R) G1 V- s2 Y+ Y: i/ B$ G4 J& D; N, ~) e
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @2 U9 k. Y5 x1 W7 @' j
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |; j1 C' ^ f* ~; b- f
2、为三多理论提供了下注的多面性奠定基础。* q! r: `/ k, E# ]; H
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路." s/ g/ m& @/ U2 k; H
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