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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O( R# |- \# p p" K; M
/ g+ j1 C7 T% e" P% B0 p6 ?( H
发现了一个有趣的现象,+ Y' R" m: j8 ?) l* _ j' ^
每一条大路,+ n" \1 q4 [! {
按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f
0 V0 R1 V; ?9 ~2 b! S8 R) J+ [按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
/ N" l" m+ ^" g- X- ~: V按4珠路排列,有4种不同的路数, G2 E3 ^" P- M) f/ Q
按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C
4 _( p! W4 m9 R1 h9 z什么意思呢,可能大家一时不清楚,
/ L. u; x+ |7 u! y5 L9 B( n8 l我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l
8 x. l$ k2 i# }. x' {) \假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u4 U# b% L# }/ V) G% b4 ]
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h; _. x* h, K$ N8 @9 m7 ^ s! x; L
够极端了吧
% s" N6 f) O3 t# q; E: V按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
; g3 n2 `9 e% e0 Q& d: Z如果我们去掉第一口,就会出现完全相反的结果:
7 V& F! j; ]: t: G3 [21212121212121212121212121212121
, J7 T! X5 @/ M/ {变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
2 J: |% X5 @4 b# i! W* y4 g( r: f# m. P如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
9 ]: |" V+ u3 z4 e% _) ^* U& d1 h所以每一条大路,! R6 V# q$ h. c; z% O: }: Y& r4 r6 R1 S3 R0 \9 I
按2珠路排列,有2种不同的路数。( b. x% A! [& @8 F& L5 T
再举一个列子:* q. A2 h2 N4 O4 b: x4 v. J
大路:122122122122122122。。。- @. k0 y# \1 P
按三珠路排列:
; b7 s& R9 b+ z! G. o$ {122,122,122,122,122,122。。。
( r' V6 w) v# k6 r0 \去掉第一口,变成:6 G2 V! \" L' c" k: d: f' k H. V9 n# \. m
221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M V0 F$ M6 ?7 u) p' o
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W6 a+ Q4 W9 N7 a5 A0 j
212,212,212,212,212,: y& l, B; I6 e- m. J# c) `& F! \8 M9 O* s7 r4 i. |
去掉3口,又返回122,122,122,了7 Q# }& U3 G f- e0 e |1 g
所以每一条大路,
1 o4 I0 D1 f/ [) n# B# @' s$ N' W0 H按3珠路排列,有3种不同的路数。2 m4 P' E; a" E- J9 ? H- a8 S# N
同理:按N珠路排列,有N种不同的路数。
4 i1 T+ R6 S! x! Z7 k4 Z我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O$ [: ^) o' t/ F7 W2 m K
字串83 L: R) G1 V- s2 Y+ Y
) d9 K: d: B7 l, B1 X- p, d3 [6 U. s5 J' [0 {1 A" m' k( @0 F( V M; u: I' z4 ?
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
* Y+ A# v" }7 U S5 Y2、为三多理论提供了下注的多面性奠定基础。2 g5 A0 L H5 `( {$ g
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.
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