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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。
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" M. v7 e4 I2 C3 F, P一般来说,* f/ K- R2 Y g; R4 P7 x
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二连赢的概率是25%, Q( t$ @/ [' y; P
# j4 q6 A9 o# {' ?三连赢的概率是12.5%* T0 \" M4 H+ h: K
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四连赢的概率是6.25%" E" q9 A( |" g4 }, Q
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……
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十连赢的概率是0.09765625%
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这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。/ H- m. F/ s; W0 y1 g$ _0 T* Y( b. Y
8 |# A# Z1 f% Y* G+ q8 j百家乐的真实概率含义是:7 b- [1 }: F6 N
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假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球
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1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。
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" P( T# m; o0 a% w# }( G, F/ q' F你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。/ p. O) c, N- N- [
, K6 x' v9 }5 ~' H9 J另外一个说法是,
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u4 D/ K1 R2 u. w9 ]1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。
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( h: o4 O" p- Q平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。3 P2 c9 L3 W$ d
8 X- j! ]5 K6 F9 v对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
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举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。$ Y/ q1 H3 |0 Z2 b* I0 x$ ? w q
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第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化: D! u. k1 m5 G' [ f- X! Z* S
- M7 Y5 t a& \% A# e第三,凯利公式的问题在于:形而上学。* P8 g/ V6 K0 C' O& E, s0 n- E/ s
" K$ o) w4 w) G# Q: Q首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。" Q D- v/ h* S R. k, [/ _
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事实上,你玩的时候,基本上每次都能打到。 R+ H+ v- d; k- t1 t& P# a
0 p5 [# ~( G }6 S3 ]因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。" n# d! X f0 @% q
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