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| 很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。 ) ]8 C% E4 T6 m9 F# k  一般来说,
 / `) R, t0 H( w5 g# q' B  二连赢的概率是25%; @  S7 ~, A) n4 k) v
 三连赢的概率是12.5%: ^% q/ p4 a  J7 j1 z' p& M" j* n
 四连赢的概率是6.25%
 9 B: h3 a% \& S- q* ~  ……: o" e. _0 |5 L% ~) \
 十连赢的概率是0.09765625%
 2 I' G2 k& A" G$ S: N. w  v5 z+ J  这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。& E: e$ w" T7 r. O" I7 `4 D
 百家乐的真实概率含义是:- x6 d0 e9 s9 Z  L
 假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球
 - {" H8 G/ ?/ w. l( w$ t' d  1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。
 9 k; Z) l5 L+ c  你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。
 V' y* t& r) J7 I% U* X$ d  你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
 * n: p$ Z: O! c8 o6 p4 n/ i. d4 A  另外一个说法是,
 ; e: l4 d  v" @+ ?& F; J" o  1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。/ C7 `% z5 ]/ H$ c: I
 2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。
 * H" r1 S: _0 I6 w5 O  再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。
 ; g2 F  i, j* W2 f- n& S: G  平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。
 1 x$ S: a3 r3 h( D4 W  对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。# s* j; z' D* Z* k" y/ t
 举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。2 m2 u" v9 u* b( c& K8 n0 U
 第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化) {2 Y) }6 P% d$ M+ o
 第三,凯利公式的问题在于:形而上学。$ O% U5 ^! w" }$ ~/ F5 ^' Y
 首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。" x2 @2 Y0 m  _1 u1 ?
 事实上,你玩的时候,基本上每次都能打到。. x+ V/ U1 u5 Q4 x+ X, {
 因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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